Electronic Formulas Page: Difference between revisions

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Looking a first measurement over the resistor
Looking a first measurement over the resistor
<syntaxhighlight>
<syntaxhighlight>
R1 = V/I
R₁ = V/I
= 1.05v ÷ 0.104A = 10.09Ω
= 1.05v ÷ 0.104A = 10.09Ω
</syntaxhighlight>
</syntaxhighlight>
Looking a second measurement over the multi-meter
Looking a second measurement over the multi-meter
<syntaxhighlight>
<syntaxhighlight>
RA = V/I
Rₐ = V/I
= 0.21v ÷ 0.104A = 2.02Ω
= 0.21v ÷ 0.104A = 2.02Ω
</syntaxhighlight>
</syntaxhighlight>
Total Resistance calculated by adding together because we are in series
Total Resistance calculated by adding together because we are in series
<syntaxhighlight>
<syntaxhighlight>
RA = V/I
Rₐ = V/I
= 10.09Ω + 2.02Ω = 12.11Ω
= 10.09Ω + 2.02Ω = 12.11Ω
</syntaxhighlight>
</syntaxhighlight>

Revision as of 01:14, 4 December 2022

Ohms Law

Ohm’s law states that the voltage across a conductor is directly proportional to the current flowing through it, provided all physical conditions and temperatures remain constant.
400
To demonstrate this a demo circuit was set up.

The circuit is put together and given the values the expected result is

1.5v ÷ 10.09Ω = 0.148A or 148mA


A you can see the answer was not as expected but instead 104.43mA. The reason for this is that the circuit has additional resistance due to the multi-meters.

Luckily we are measuring these values

Looking a first measurement over the resistor

R₁ = V/I
= 1.05v ÷ 0.104A = 10.09Ω

Looking a second measurement over the multi-meter

Rₐ = V/I
= 0.21v ÷ 0.104A = 2.02Ω

Total Resistance calculated by adding together because we are in series

Rₐ = V/I
= 10.09Ω + 2.02Ω = 12.11Ω

Calculating the Total Amps

Amps = V/I
= 1.5 ÷ 12.11Ω = 0.123A or 123mA

Now lets calculate the Total Resistance using actual current meter reading (0.104A) and the (1.5) voltage.

R"T" = V/I
     = 1.5v / 0.104A = 14.4Ω

Given we now know the actual resistance and the total resistance gives to the wiring resistance.

= 14.4Ω (calculated from the meter reading and the input voltage) - 12.11Ω (Calculated from total resistance) = 2.29Ω