Electronic Formulas Page: Difference between revisions
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Looking a first measurement over the resistor | Looking a first measurement over the resistor | ||
<syntaxhighlight> | <syntaxhighlight> | ||
R₁ = V/I | |||
= 1.05v ÷ 0.104A = 10.09Ω | = 1.05v ÷ 0.104A = 10.09Ω | ||
</syntaxhighlight> | </syntaxhighlight> | ||
Looking a second measurement over the multi-meter | Looking a second measurement over the multi-meter | ||
<syntaxhighlight> | <syntaxhighlight> | ||
Rₐ = V/I | |||
= 0.21v ÷ 0.104A = 2.02Ω | = 0.21v ÷ 0.104A = 2.02Ω | ||
</syntaxhighlight> | </syntaxhighlight> | ||
Total Resistance calculated by adding together because we are in series | Total Resistance calculated by adding together because we are in series | ||
<syntaxhighlight> | <syntaxhighlight> | ||
Rₐ = V/I | |||
= 10.09Ω + 2.02Ω = 12.11Ω | = 10.09Ω + 2.02Ω = 12.11Ω | ||
</syntaxhighlight> | </syntaxhighlight> |
Revision as of 01:14, 4 December 2022
Ohms Law
Ohm’s law states that the voltage across a conductor is directly proportional to the current flowing through it, provided all physical conditions and temperatures remain constant.
To demonstrate this a demo circuit was set up.
The circuit is put together and given the values the expected result is
1.5v ÷ 10.09Ω = 0.148A or 148mA
A you can see the answer was not as expected but instead 104.43mA. The reason for this is that the circuit has additional resistance due to the multi-meters.
Luckily we are measuring these values
Looking a first measurement over the resistor
R₁ = V/I
= 1.05v ÷ 0.104A = 10.09Ω
Looking a second measurement over the multi-meter
Rₐ = V/I
= 0.21v ÷ 0.104A = 2.02Ω
Total Resistance calculated by adding together because we are in series
Rₐ = V/I
= 10.09Ω + 2.02Ω = 12.11Ω
Calculating the Total Amps
Amps = V/I
= 1.5 ÷ 12.11Ω = 0.123A or 123mA
Now lets calculate the Total Resistance using actual current meter reading (0.104A) and the (1.5) voltage.
R"T" = V/I
= 1.5v / 0.104A = 14.4Ω
Given we now know the actual resistance and the total resistance gives to the wiring resistance.
= 14.4Ω (calculated from the meter reading and the input voltage) - 12.11Ω (Calculated from total resistance) = 2.29Ω