Electronic Formulas Page: Difference between revisions

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Total Resistance calculated by adding together because we are in series
Total Resistance calculated by adding together because we are in series
<syntaxhighlight>
<syntaxhighlight>
Rₐ = V/I
Rₜ = V/I
= 10.09Ω + 2.02Ω = 12.11Ω
= 10.09Ω + 2.02Ω = 12.11Ω
</syntaxhighlight>
</syntaxhighlight>
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Now lets calculate the Total Resistance using actual current meter reading  (0.104A) and the (1.5) voltage.
Now lets calculate the Total Resistance using actual current meter reading  (0.104A) and the (1.5) voltage.
<syntaxhighlight>
<syntaxhighlight>
R"T" = V/I
R"" = V/I
     = 1.5v / 0.104A = 14.4Ω
     = 1.5v / 0.104A = 14.4Ω
</syntaxhighlight>
</syntaxhighlight>

Revision as of 01:15, 4 December 2022

Ohms Law

Ohm’s law states that the voltage across a conductor is directly proportional to the current flowing through it, provided all physical conditions and temperatures remain constant.
400
To demonstrate this a demo circuit was set up.

The circuit is put together and given the values the expected result is

1.5v ÷ 10.09Ω = 0.148A or 148mA


A you can see the answer was not as expected but instead 104.43mA. The reason for this is that the circuit has additional resistance due to the multi-meters.

Luckily we are measuring these values

Looking a first measurement over the resistor

R₁ = V/I
= 1.05v ÷ 0.104A = 10.09Ω

Looking a second measurement over the multi-meter

Rₐ = V/I
= 0.21v ÷ 0.104A = 2.02Ω

Total Resistance calculated by adding together because we are in series

Rₜ = V/I
= 10.09Ω + 2.02Ω = 12.11Ω

Calculating the Total Amps

Amps = V/I
= 1.5 ÷ 12.11Ω = 0.123A or 123mA

Now lets calculate the Total Resistance using actual current meter reading (0.104A) and the (1.5) voltage.

R"ₜ" = V/I
     = 1.5v / 0.104A = 14.4Ω

Given we now know the actual resistance and the total resistance gives to the wiring resistance.

= 14.4Ω (calculated from the meter reading and the input voltage) - 12.11Ω (Calculated from total resistance) = 2.29Ω